Equation of the circle having centre at (3,−1)  and cutting the intercept of length 6 units on the line 2x−5y+18=0  is

Given that centre C(3,−1)  and line is 2x-5y+18=0….(1) d =perpendicular distance from centre to (1)=|6+5+18|4+25=29 Since circle cuts the intercept is 6 ⇒2r2−d2=6 ⇒r2−29=3 ⇒r2=38 ∴ Equation of the circle is (x−h)2+(y−k)2=r2 ⇒(x−3)2+(y+1)2=38 ⇒x2+y2−6x+2y−28=0