Questions
The equation of the circle passing through ( 4, 3 having the centre (2, 2), is
a
x2+y2+4x+4y−5=0
b
x2+y2−4x−4y−5=
c
x2+y2−4x=13
d
x2+y2−4x−4y+5=0
detailed solution
Correct option is B
Radius of the circle is (4−2)2+(5−2)2=13So, equation of the circle is(x−2)2+(y−2)2=13 or, x2+y2−4x−4y−5=0Talk to our academic expert!
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