Equation of the circle through the origin and making intercepts of 3 and 4 on the positive sides of the axes is
x2+y2+3x+4y=0
x2+y2−3x−4y=0
x2+y2+3x−4y=0
x2+y2−3x+4y=0
The circle passes through (0, 0), (3, 0) and (0, 4). So, its equation is x2+y2−3x−4y=0