Questions
Equation of the circle through the origin and making intercepts of and on the positive sides of the axes is
a
x2+y2+3x+4y=0
b
x2+y2−3x−4y=0
c
x2+y2+3x−4y=0
d
x2+y2−3x+4y=0
detailed solution
Correct option is B
The circle passes through (0, 0), (3, 0) and (0, 4). So, its equation is x2+y2−3x−4y=0Talk to our academic expert!
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