The equation of a circle which cuts the three circles
orthogonally, is
The circle having centre at the radical centre of three given circles and radius equal to the length of the tangent from it to any one of three circles cuts all the three circles orthogonally. The given circles are
…(i)
…(ii)
…(iii)
The radical axes of (i), (ii) and (ii), (iii) are respectively
…(iv)
and, …(v)
Solving (iv) and (v), we get
Thus, the coordinates of the radical centre are The length of the tangent from to circle (i) is given by
Hence, the required circle is