The equation of the circle which has normal $(\mathrm{x}-1)\times (\mathrm{y}-2)=0$ and a tangent $3\mathrm{x}+4\mathrm{y}=6$is

• A

  ${\mathrm{x}}^2+{\mathrm{y}}^2-2\mathrm{x}-4\mathrm{y}+4=0$

• B

  ${\mathrm{x}}^2+{\mathrm{y}}^2-2\mathrm{x}-4\mathrm{y}+5=0$

• C

  ${\mathrm{x}}^2+{\mathrm{y}}^2=5$

• D

  ${(\mathrm{x}-3)}^2+{(\mathrm{y}-4)}^2=5$