The equation of the circle which has normal (x$$−$$1)×$$(y$$−$$2)=0$$ and a tangent $$3x+4y=6$$ is

Correct option is 1x2+y2−2x−4y+4=0

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The equation of the circle which has normal $(x - 1) \times (y - 2) = 0$ and a tangent $3 x + 4 y = 6$ is

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x2+y2−2x−4y+4=0

x2+y2−2x−4y+5=0

x2+y2=5

(x−3)2+(y−4)2=5

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detailed solution

Correct option is A

x-1=0,y-2=0centre is(1,2),radius is perpendicular distance from centre to tangent3x+4y=6

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The equation of the circle which has normal (x−1)×(y−2)=0 and a tangent 3x+4y=6 is

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The equation of the circle which has normal $(x - 1) \times (y - 2) = 0$ and a tangent $3 x + 4 y = 6$ is