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Q.

The equation of the circle which has normal (x−1)×(y−2)=0 and a tangent 3x+4y=6 is

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a

x2+y2−2x−4y+4=0

b

x2+y2−2x−4y+5=0

c

x2+y2=5

d

(x−3)2+(y−4)2=5

answer is A.

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Detailed Solution

x-1=0,y-2=0centre is(1,2),radius is perpendicular distance from centre to tangent3x+4y=6
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