The equation of the circle which has a tangent 2x−y−1=0 at (3,5) on it and with the centre on x+y=5 is
x2+y2+6x−16y+28=0
x2+y2−6x+16y−28=0
x2+y2+6x+6y−28=0
x2+y2−6x−6y−28=0
The equation of the family of circles touching 2x−y−1=0 at (3,5) is
(x−3)2+(y−5)2+λ(2x−y−1)=0 ... (1)
It has its centre −λ+3,λ+102 on the line x+y=5
∴ −λ+3+λ+102=5⇒λ=6
Putting λ=6 in (i), we get
as the equation of the required circle.