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Q.

The equation of the circle which has a tangent 2x−y−1=0 at (3,5) on it and with the centre on x+y=5 is

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a

x2+y2+6x−16y+28=0

b

x2+y2−6x+16y−28=0

c

x2+y2+6x+6y−28=0

d

x2+y2−6x−6y−28=0

answer is A.

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Detailed Solution

The equation of the family of circles touching 2x−y−1=0 at (3,5) is(x−3)2+(y−5)2+λ(2x−y−1)=0                    ... (1)It has its centre −λ+3,λ+102 on the line x+y=5∴ −λ+3+λ+102=5⇒λ=6Putting λ=6 in (i), we getx2+y2+6x−16y+28=0as the equation of the required circle.
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