The equation of the circle which has a tangent 2x−y−1=0 at (3,5) on it and with the centre on x+y=5 is
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a
x2+y2+6x−16y+28=0
b
x2+y2−6x+16y−28=0
c
x2+y2+6x+6y−28=0
d
x2+y2−6x−6y−28=0
answer is A.
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Detailed Solution
The equation of the family of circles touching 2x−y−1=0 at (3,5) is(x−3)2+(y−5)2+λ(2x−y−1)=0 ... (1)It has its centre −λ+3,λ+102 on the line x+y=5∴ −λ+3+λ+102=5⇒λ=6Putting λ=6 in (i), we getx2+y2+6x−16y+28=0as the equation of the required circle.