The equation of the circle which has a tangent 2x−y−1=0 at (3,5) on it and with the centre on x+y=5 is
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
x2+y2+6x−16y+28=0
b
x2+y2−6x+16y−28=0
c
x2+y2+6x+6y−28=0
d
x2+y2−6x−6y−28=0
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
The equation of the family of circles touching 2x−y−1=0 at (3,5) is(x−3)2+(y−5)2+λ(2x−y−1)=0 ... (1)It has its centre −λ+3,λ+102 on the line x+y=5∴ −λ+3+λ+102=5⇒λ=6Putting λ=6 in (i), we getx2+y2+6x−16y+28=0as the equation of the required circle.