First slide
Analysis of two circles in circles
Question

The equation of a circle which passes through (2a, 0) and whose radical axis in relation to the circle x2+y2=a2 is x=a/2, is

Moderate
Solution

The required circle is

x2+y2a2+λxa2=0            [Using: S+λL=0 ] 

This passes through (2a,0)

 4a2a2+3a2λ=0λ=2a

Hence, the required circle is 

x2+y2a22axa2=0x2+y2a22ax+a2=0x2+y22ax=0

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