The equation of a circle which passes through (2a, 0) and whose radical axis in relation to the circle x2+y2=a2 is x=a/2, is

The required circle isx2+y2−a2+λx−a2=0            [Using: S+λL=0 ] This passes through (2a,0)∴ 4a2−a2+3a2λ=0⇒λ=−2aHence, the required circle is x2+y2−a2−2ax−a2=0⇒x2+y2−a2−2ax+a2=0⇒x2+y2−2ax=0