The equation of the circle which touches the axes of the coordinates and the line x3+y4=1and whose centre lies in the first quadrant isx2 + y2 - 2cx -2cy + c2 = 0,where c, is

The equation of a circle touching the coordinate axes is                   (x−c)2+(y−c)2=c2This touches x3+y4=1, i.e. 4x+3y−12=0∴ 4c+3c−1242+32=c⇒|7c−12|=5c⇒c=6,1Thus, the equation of the required circle is    x2+y2−2cx−2cy+c2=0, where c=1,6