Q.

The equation of the circle whose centre is(2, - 3) and radius 5, is

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a

x2+y2+4x−6y−12=0

b

x2+y2−4x+6y−12=0

c

x2+y2−6x+4y−12=0

d

none of these

answer is B.

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Detailed Solution

The equation of the required circle is(x−2)2+(y+3)2=52⇒x2+y2−4x+6y−12=0
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