The equation of the circle whose centre is
(2, - 3) and radius 5, is
x2+y2+4x−6y−12=0
x2+y2−4x+6y−12=0
x2+y2−6x+4y−12=0
none of these
The equation of the required circle is
(x−2)2+(y+3)2=52⇒x2+y2−4x+6y−12=0