Q.
Equation of circle whose radius is 5 and which touches the circle x2+y2−2x−4y−20=0 at (5, 5) is
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a
(x−9)2+(y−8)2=5
b
(x−9)2+(y+8)2=25
c
x2+y2=25
d
(x−9)2+(y−8)2=25
answer is D.
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Detailed Solution
C1=(1,2) r1=5 C2=(h,k) r2=5As the two circles radii are same the point where the two circles touch each other is the midpoint of the centres(5,5)=(h+12,k+22)⇒(h,k)=(9,8)∴(x−9)2+(y−8)2=25
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