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Q.

Equation of circle whose radius is 2 and which touches internally the circle x2+y2+4x−8y−5=0  at (1, 0) is

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a

(x−15)2+(y−85)2=4

b

(x+15)2+(y+85)2=4

c

(x+15)2+(y−85)2=4

d

(x−15)2+(y+85)2=4

answer is C.

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Detailed Solution

C1=(−2,4),r1=5r2=2,P(1,0)C2 divides C1P in the ratio 3:2C2=(−15,85)
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