Questions
Equation of a circle with centre touching internally and containing the circle is
a
x2+y2+8x−6y+9=0
b
x2+y2−8x+6y+9=0
c
x2+y2+8x−6y−11=0
d
x2+y2−8x+6y−11=0
detailed solution
Correct option is C
Let the equation of the required circle be. (x+4)2+(y−3)2=r2 (i)If (i) touches the circle x2+y2=1 internally (ii)the distance between the centres (- 4, 3) and (0, 0) of these circles is equal to the difference of their radii⇒ 42+32=r−1⇒r=5+1⇒r=6So that an equation of the required circle isx2+y2+8x−6y−11=0.Talk to our academic expert!
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