Equation of the circle with centre on the y-axis and passing through the origin and the point (2, 3) is

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x2+y2+13y=0

3x2+3y2+13x+3=0

6x2+6y2−13x=0

3x2+3y2−13y=0

answer is D.

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Detailed Solution

Let center =C(0,k) Circle passes through O(0,0) and A(2,3)OC2=AC2⇒k=13/6 Radius =13/6 Equation of the required circle is 3x2+3y2−13y=0

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