Equation of the circle with centre on the y-axis and passing through the origin and the point (2, 3) is
x2+y2+13y=0
3x2+3y2+13x+3=0
6x2+6y2−13x=0
3x2+3y2−13y=0
Let center =C(0,k)
Circle passes through O(0,0) and A(2,3)OC2=AC2⇒k=13/6
Radius =13/6
Equation of the required circle is 3x2+3y2−13y=0