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Q.

The equation of a circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3 a is

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a

x2+y2=9a2

b

x2+y2=16a2

c

x2+y2=4a2

d

x2+y2=a2

answer is C.

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Detailed Solution

It is given that the triangle is equilateral. Therefore, centroid of the triangle is same as the circumcircle.Also, Radius of the circumcircle =23 (median) =23(3a)=2aHence, the equation of the circumcircle whose centre is at(0, 0) and radius 2a, is x2+y2=(2a)2
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