The equation of the circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
x2+y2=9a2
b
x2+y2=16a2
c
x2+y2=4a2
d
x2+y2=a2
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
As the centre of the circumcircle of an equilateral triangle is its Centroid and the distance of the Centroid from the vertex of the triangle is 2/3 of its medium through the vertex. So the distance of the centre from a vertex of the triangle is (2/3)×3a=2a and hence the vertex of the circumcircle is x2+y2=4a2