The equation of the circle with radius 3 and centre as the point of intersection of the lines 2x+3y=5 , 2x−y=1 is
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a
x2+y2=9
b
x2+y2−2x−2y−7=0
c
x2+y2−2x−2y+7=0
d
x2+y2+9=0
answer is B.
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Detailed Solution
Given lines are 2x+3y=5…..(1), 2x−y=1….(2) Point of Intersection of (1)&(2)= (1,1)=(h,k)r=3Equation of circle is (x−h)2+(y−k)2=r2⇒(x−1)2+(y−1)2=9⇒x2+y2−2x−2y−7=0