Equation of circles touching x-axis at the  origin and the line 4x−3y+24=0  are

Given line is 4x−3y+24=0 Since equation of  circles touching x-axis at the origin thenCentre = (0, r)radius, r=d =The perpendicular distance from centre to the line⇒r=|0−3r+24|5∴r=12,   r=3∴ The equation of the circle is (x−h)2+(y−k)2=r2(x−0)2+(y−3)2=9  or(x−0)2+(y+12)2=144⇒x2+y2−6y=0,x2+y2+24y=0