The equation of the common tangent to the circle (x-3)2+y2=9 and the parabola y2=4x, above the x-axis is

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3 y=3x+1

3y=−x+3

3y=x+3

3 y=−3x+1

answer is C.

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Detailed Solution

Equation of the tangent to y2=4x is y=mx+1m→1(1) is a tangent to circle with center ( 3, 0) and r = 3r=d⇒3=3m+1m1+m2m=±13If m=13⇒y=x3+3

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