First slide
Hyperbola in conic sections
Question

Equation of a common tangent to the curves y2 = 8x and xy =  1 is 

Moderate
Solution

Equation of a tangent at at2,2at  to y2=8x

ty=x+at2  where 4a=8 i.e. a=2

 ty=x+2t2 which intersects the curve xy=1 

at the points given by xx+2t2t=1 clearly t0 

or x2+2t2x+t=0 and will be a tangent to the curve if the roots of this quadratic equation are equal, for which 

4t4  4t = 0 t = 0 or t = 1 and an equation of a common tangent is y = x + 2.

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