Equation of a common tangent to the curves y2 = 8x and xy = – 1 is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
3y=9x+2
b
y=2x+1
c
2y=x+8
d
y=x+2
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Equation of a tangent at at2,2at to y2=8xty=x+at2 where 4a=8 i.e. a=2⇒ ty=x+2t2 which intersects the curve xy=−1 at the points given by xx+2t2t=−1 clearly t≠0 or x2+2t2x+t=0 and will be a tangent to the curve if the roots of this quadratic equation are equal, for which 4t4 – 4t = 0⇒ t = 0 or t = 1 and an equation of a common tangent is y = x + 2.