Questions
a
3y = 9x+2
b
y=2x+1
c
2y=x+8
d
y=x+2
detailed solution
Correct option is D
A point on the curve xy=−1 is of the form (t,−1/t). Now y=−1x⇒dydx=1x2⇒dydx(t,−1/t)=1t2∴ Equation of tangent to the curve xy=−1 at (t,−1/t) is y+1t=1t2(x−t)⇒y=1t2x−2t For this line to be tangent to the parabola y2=8x it should be of the form y=mx+2m so m=1t2 and −2t=2m or m=−t∴ −t=1t2⇒−t3=1⇒t=−1 Thus the required tangent is _y=x+2.Talk to our academic expert!
Similar Questions
The curve y= ax3+ bx2+cx + 5 touches the x-axis at P(-2, 0) and cuts the y-axis at a point Q where its gradient is 3, then the value of -10 a- 100b+ 1000 c must be
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
Popular Books
HC Verma Part 1HC Verma Part 2RS AgarwalRD SharmaLakhmir SinghDK GoelSandeep GargTS GrewalNCERT solutions
Class 12 NCERT SolutionsClass 11 NCERT SolutionsClass 10 NCERT SolutionsClass 9 NCERT SolutionsClass 8 NCERT SolutionsClass 7 NCERT SolutionsClass 6 NCERT Solutions
