Download the app

Questions  

An equation of a common tangent to the parabola

y2=4x and x2=4y is 

a
x – y + 1 = 0
b
x + y – 1 = 0
c
x + y + 1 = 0
d
y = 0

detailed solution

Correct option is C

Equation of a tangent to y2=4x is y=mx+1/mIf it touches the parabola x2=4y then the roots ofthe equation x2=4(mx+1/m) are coincident. So(4m)2+16m=0⇒m=−1 and the equation ofthe tangent is x + y + 1 = 0.

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

The length of the perpendiculars from the focus
and the extremities of a focal chord of a parabola
on the tangent at the vertex form


phone icon
whats app icon