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Correct option is C
The equation of tangent to the given parabola having slope m is y=mx+1m----(1) The equation of tangent to the given circle having slope m is y=m(x−3)±31+m2---(2)Equations ( 1) and (2) are identical. So, 1m=−3m±31+m2 or 1+3m2=±3m1+m2 or 1+6m2+9m4=9m2+m4 or 3m2=1 or m=±13 Hence, the equation of common tangent is 3y=x+3(as tangent is lying above the x-axis).Talk to our academic expert!
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The length of the perpendiculars from the focus
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