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The equation $(\cos p - 1) x^{2} + (\cos p) x + \sin p = 0$ in the variable x has real roots. Then p can take any value in the interval

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0,2π

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Correct option is D

Since the equation cosp−1x2+cospx+sinp=0 has real roots ⇒b2-4ac≥0⇒cos2p−4sinpcosp−1≥0⇒since cos2p≥0 and cosp−1≤0,One of the possibilities for the inequality to hold good is sinp≥0⇒p∈0,π

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The equation cosp−1x2+cospx+sinp=0 in the variable x has real roots. Then p can take any value in the interval

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The equation $(\cos p - 1) x^{2} + (\cos p) x + \sin p = 0$ in the variable x has real roots. Then p can take any value in the interval