The equation 2cos2x2sin2x=x2+1x2,0≤x≤π2 has
no real solution
one real solution
more than one real solution
none of these
Clearly ,
LHS =2cos2(x/2)sin2x≤2 and, RHS =x2+1x2≥2
Thus, the equality holds when each side is equal to 2.
But, RHS is equal to 2 for x =1 while LHS is less than 2 for this value of x.
Consequently the equation has no solution.