First slide
Theory of expressions
Question

The equation 2cos2x2sin2x=x2+1x2,0xπ2 has   

Moderate
Solution

Clearly , 

 LHS =2cos2(x/2)sin2x2 and,  RHS =x2+1x22

Thus, the equality holds when each side is equal to 2. 

But, RHS is equal to 2 for x =1 while LHS is less than 2 for this value of x

Consequently the equation has no solution. 

 

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