First slide

Methods of solving first order first degree differential equations

Question

$The equation of the curve passing through (0, 1) which is a solution of$ $differential equation (1 + y^{2}) dx + (1 + x^{2}) dy = 0 is λ ({Tan}^{- 1} x + {Tan}^{- 1} y) = π then λ is$

Easy

Solution

$\begin{array}{l} \int \frac{dx}{1 + x^{2}} + \int \frac{dy}{1 + y^{2}} = \int 0 \\ \Rightarrow {Tan}^{- 1} x + {Tan}^{- 1} y = c \\ Pass (0, 1) \\ \to c = π / 4 \\ \Rightarrow 4 ({Tan}^{- 1} x + {Tan}^{- 1} y) = π \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App