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Methods of solving first order first degree differential equations

Question

 The equation of the curve passing through (0,1) which is a solution of  differential equation 1+y2dx+1+x2dy=0 is λTan1x+Tan1y=π then λ is 

Easy
Solution

 dx1+x2+dy1+y2=0Tan1x+Tan1y=cPass(0,1)c=π/44Tan1x+Tan1y=π



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The general solution of the differential equation 1+y2dx+1+x2dy=0 is


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