The equation of the curve satisfying the differential equation  y2x2+1=2xdydx passing through the point (1,1) is

Given differential equation after rearranging the terms is∫x2+12xdx=∫dyy212∫x dx+∫1xdx=∫dyy2⇒12x22+ln⁡x=−1y+C∵ It passes through (1,1)⇒14=−1+C⇒C=54⇒1y=54−x2+2ln⁡x4⇒y=45−x2−2ln⁡x