Q.

The equation esinx−e−sinx−4=0 has:

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a

Infinite number of real roots

b

no real roots

c

exactly one real root

d

exactly four real roots

answer is B.

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Detailed Solution

Given equation is  esinx−e−sinx−4=0  put esinx=t in the given equation, we get t2−4t−1=0 ⇒t=4±252=2±5            ⇒esinx=2±5     (∵t=esinx)⇒esinx=2−5 and esinx=2+5esinx=2−5<0 is not possible∴esinx=2+5 ⇒sinx=ln2+5>1 This is not true. ∴There is no solution for the given equation.
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