Q.
The equation esinx−e−sinx−4=0 has:
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a
Infinite number of real roots
b
no real roots
c
exactly one real root
d
exactly four real roots
answer is B.
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Detailed Solution
Given equation is esinx−e−sinx−4=0 put esinx=t in the given equation, we get t2−4t−1=0 ⇒t=4±252=2±5 ⇒esinx=2±5 (∵t=esinx)⇒esinx=2−5 and esinx=2+5esinx=2−5<0 is not possible∴esinx=2+5 ⇒sinx=ln2+5>1 This is not true. ∴There is no solution for the given equation.
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