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$The equation of ellipse circumscribing the quadrilateral whose sides are given by x =±2 and y = ±4 and$
$distance between foci is 4 \sqrt{6}, is$

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x232+y28=1

x28+y232=1

x216+y28−1

x28+y216=1

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detailed solution

Correct option is B

Let equation be x2a2+y2b2=1 where a2=b21−e2Ellipse passes through the point (2,4).∴ 4a2+16b2=1---(i) Also distance between foci is 46 . ∴ be=26∴ 4b2−24+16b2=1⇒ b4−44b2+16×24=0⇒ b2−32b2−12=0⇒ b2=32( as b>4)⇒ a2=8

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The equation of ellipse circumscribing the quadrilateral whose sides are given by x =±2 and y = ±4 and distance between foci is 46, is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

$The equation of ellipse circumscribing the quadrilateral whose sides are given by x =±2 and y = ±4 and$
$distance between foci is 4 \sqrt{6}, is$