The equation of ellipse circumscribing the quadrilateral whose sides are given by x =±2 and y = ±4 and
distance between foci is 46, is
x232+y28=1
x28+y232=1
x216+y28−1
x28+y216=1
Let equation be x2a2+y2b2=1 where a2=b21−e2
Ellipse passes through the point (2,4).
∴ 4a2+16b2=1---(i) Also distance between foci is 46 .
∴ be=26∴ 4b2−24+16b2=1⇒ b4−44b2+16×24=0⇒ b2−32b2−12=0⇒ b2=32( as b>4)⇒ a2=8