Equation of the ellipse having centre at origin and touching the hyperbola x225−y216=1 at its vertices and having eccentricity 3/5 is

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x225+y216=1

x216−y225=1

x29+y216=1

x216+y29=1

answer is A.

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Detailed Solution

a=5b2=a21−e2=251−925=16.⇒b=4∴x225+y216=1