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Equation of the ellipse having centre at origin and touching the hyperbola x225−y216=1 at its vertices and having eccentricity 3/5 is
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a
x225+y216=1
b
x216−y225=1
c
x29+y216=1
d
x216+y29=1
answer is A.
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Detailed Solution
a=5b2=a21−e2=251−925=16.⇒b=4∴x225+y216=1
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