Equation of an ellipse with centre at the origin passing  through  (5,0) and having eccentricity 2/3  is.

Let the equation of the ellipse be x2a2+y2b2=1.It  passes through  (5,0)⇒a2=25b2=a21−e2⇒b2=251−49=1259Hence the required equation of the ellipse is    5x2+9y2 =25