Equation of an ellipse with centre at the origin passing through (5,0) and having eccentricity 2/3 is.
16x2+5y2 =25
9x2+5y2 =25
5x2+9y2 =25
5x2+16y2 =25
Let the equation of the ellipse be x2a2+y2b2=1.
It passes through (5,0)⇒a2=25
b2=a21−e2⇒b2=251−49=1259
Hence the required equation of the ellipse is