Questions
Equation of an ellipse with centre at the origin passing through and having eccentricity is.
a
16x2+5y2 =25
b
9x2+5y2 =25
c
5x2+9y2 =25
d
5x2+16y2 =25
detailed solution
Correct option is C
Let the equation of the ellipse be x2a2+y2b2=1.It passes through (5,0)⇒a2=25b2=a21−e2⇒b2=251−49=1259Hence the required equation of the ellipse is 5x2+9y2 =25Talk to our academic expert!
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If is an equation of the line joining the extremities of a pair of semi-conjugate diameters of t the ellipse
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