Questions
The equation of the family of curves which intersect the hyperbola xy=2 orthogonally is
a
y=x36+c
b
y=x24+c
c
y=-x24+c
d
y=-x36+c
detailed solution
Correct option is A
y=2/xdydx=−2x2 Let y=d(x) be the required family of curves then dydxc1dydxc2=−1→dydxx−2x2=−1→dydx=x22⇒y=x36+cTalk to our academic expert!
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