The equation formed by decreasing each root of ax2+bx+c=0 by 2 is 3x2+6x+2=0 , then
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
3a+b=0
b
b+3c=0
c
3b+c=0
d
b+c=0
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
The given equation ax2+bx+c=0 …… ( 1 ) Eq. ( 1 ) is decreasing each root by 2 ax2+bx+c=3(x−2)2+6(x−2)+2 =3(x2+4−4x)+6x−12+2 ⇒ax2+bx+c=3x2−6x+2 Equating the coefficients, we geta=3,b=−6,c=2 Check these values through given options, b+3c=0 is satisfies.