The equation of the horizontal tangents of the graphs of the function y=ex+e−x is

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y=−2

y=2

y=3

y=−3

answer is B.

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Detailed Solution

The slope of the horizontal tangent is 0 So 0=dydx=ex−e−x⇒e2x=1⇒x=0 If x = 0 then y = 2Hence the equation of horizontal tangent at (0,2) is y = 2

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