Equation of the line equidistant from the parallel lines 9x+6y−7=0 and 3x+2y+6=0 is

The given lines are 3x + 2y + 6 = 0  and 3x+2y−73=0Let the required line be 3x + 2y + k = 0. Since it is equidistant from the given lines k+739+4=6−k9+4 ⇒ k=116