Equation of the line equidistant from the parallel lines
9x+6y−7=0 and 3x+2y+6=0 is
6x + 4y + 5 = 0
18x + 12y + 11 = 0
18x + 12y – 11 = 0
12x + 8y + 7 = 0
The given lines are 3x + 2y + 6 = 0 and 3x+2y−73=0
Let the required line be 3x + 2y + k = 0.
Since it is equidistant from the given lines
k+739+4=6−k9+4 ⇒ k=116