Questions
can be written as
a
x−12=y+2−3=z4
b
x−12=y−23=z4
c
x2=y+13=z−24
d
x2=y3=z−24
detailed solution
Correct option is B
Given equation of planes are 4x+4y−5z=12−−−−−(i) And 8x+12y−13z=32−−−−−(ii) Let DR's of required line be (l,m,n)From Eq’s (i) and (ii) we get 4l+4m−5n=0 And 8l+12m−13n=0⇒l8=m12=n16⇒l2=m3=n4 Now we take intersection point with z=0 is given by 4x+4y=12−−−−(iii) And 8x+12y=32−−−−(iv) On solving Equations (i) and (ii) we get the point (1,2,0) Required line is x−12=y−23=z4Talk to our academic expert!
Similar Questions
In the if , B = (3,2,0) and C = (0,1,4) then the length of the median passing through A is
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