Questions
The equation of line of intersection of two planes in symmetric form is
a
x2=y−21=z−34
b
x−22=y−21=z4
c
x−22=y1=z−34
d
x−22=y-1=z+34
detailed solution
Correct option is A
The given planes are 4x−4y−z+11=x+2y−z−1=0 To get a point on the line, substitute x=0 in above equations and then solve for the other coordinates y=2, z=3Hence, a point on the line is 0,2,3The direction ratios are proportional to the components of the vector ijk4−4−112−1=i(6)−j(−3)+k(12)Hence, the direction ratios of the required line are in proportion with ⟨2,1,4⟩Therefore, the equation of the line is x2=y−21=z−34Talk to our academic expert!
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