The equation of line of intersection of two planes 4x−4y−z+11=x+2y−z−1=0 in symmetric form is

The given planes are 4x−4y−z+11=x+2y−z−1=0 To get a point on the line, substitute x=0 in above equations and then solve for the other coordinates y=2, z=3Hence, a point on the line is 0,2,3The direction ratios are proportional to the components of the vector ijk4−4−112−1=i(6)−j(−3)+k(12)Hence, the direction ratios of the required line are in proportion with ⟨2,1,4⟩Therefore, the equation of the line is x2=y−21=z−34