Questions
Equation of line parallel to the line and passing through the point is
a
x−12=y−2−3=z−38
b
x+12=y−2−3=z−38
c
x−4−1=y+12=z+103
d
x1=y2=z2
detailed solution
Correct option is B
The equation of the line passing through the point x1,y1,z1and parallel to the line x−x2a=y−y2b=z−z2cisx−x1a=y−y1b=z−z1cHere the given point is −1,2,3and the equation of the line isx−42=y+1−3=z+108Therefore, the equation of the required line is x+12=y−2−3=z−38Talk to our academic expert!
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