Equation of line parallel to the line  x−42=y+1−3=z+108and passing through the point −1,2,3is

The equation of the line passing through the point  x1,y1,z1and parallel to the line x−x2a=y−y2b=z−z2cisx−x1a=y−y1b=z−z1cHere the given point is  −1,2,3and the equation of the line isx−42=y+1−3=z+108Therefore, the equation of the required line is  x+12=y−2−3=z−38