The equation of the line passing through (-1, 2, -3 ) and perpendicular to the plane 2x+3y+z+5=0 is

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x−1−1=y+21=z−3−1

x+1−1=y−21=z+31

x+12=y−23=z+31

x+11=y−21=z+31

answer is C.

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Detailed Solution

By verify the options required line satisfied line by the given point and apply the perpendicular condition of line and planeline d r s is equal to plane normal d.r

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