Equation of a line passing through -1,2,-3 and perpendicular to the plane 2x+3y+z+5=0 is

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x−1−1=y+21=z−3−1

x+1−1=y−21=z+31

x+12=y−23=z+31

x+1−1=y−2−1=z+31

answer is C.

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Detailed Solution

The direction ratios of any line perpendicular to the plane ax+by+cz+d=0 are proportional to ⟨a,b,c⟩Equation of the given plane is 2x+3y+z+5=0 The direction ratios of line perpendicular to the above plane are ⟨2,3,1⟩Therefore, the equation of the line passing through the point -1,2,-3 and perpendicular to the plane 2x+3y+z+5=0 is x+12=y−23=z+31

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