Q.

Equation of a line passing through -1,2,-3 and perpendicular to the plane 2x+3y+z+5=0 is

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a

x−1−1=y+21=z−3−1

b

x+1−1=y−2−1=z+31

c

x+12=y−23=z+31

d

x+11=y−21=z+31

answer is C.

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Detailed Solution

The direction ratios of normal to the plane 2x+3y+z+5=0 are ⟨2,3,1⟩Hence the equation of the line passing through the point -1,2,-3 and having direction ratios ⟨2,3,1⟩ is x+12=y−23=z+31
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