Q.
Equation of line passing through the point (1,0,3)and parallel to a line whose direction ratios are ⟨3,6,2⟩is
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a
x−31=y−62=z−23
b
x−31=y−60=z−23
c
x−13=y−06=z−32
d
x−12=y6=z−3−1
answer is C.
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Detailed Solution
The equation of the line passing through the point(x1,y1,z1) and parallel to the line whose direction ratios are ⟨a,b,c⟩ is x−x1a=y−y1b=z−z1cHere the given point is (1,0,3) and the direction ratios are ⟨3,6,2⟩Therefore, the equation of the required line is x−13=y6=z−32
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