Questions
Equation of the line passing through the point and perpendicular to the plane
a
x−1−1=y+21=z−3−1
b
x+1−1=y−21=z+31
c
x+12=y−23=z+31
d
x+y−3=y−12=z−31
detailed solution
Correct option is C
The direction ratios of any line perpendicular to the plane ax+by+cz+d=0are proportional toa,b,cThe equation of the line passing through the point x1,y1,z1and parallel to the line whose direction ratios are a,b,cisx−x1a=y−y1b=z−z1cHence, the equation of the line passing through the point −1,2,−3and perpendicular to the plane 2x+3y+z+5=0is x+12=y−23=z+31Talk to our academic expert!
Similar Questions
The equation of the plane which passes through the z-axis and is perpendIcular to the line is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
Popular Books
HC Verma Part 1HC Verma Part 2RS AgarwalRD SharmaLakhmir SinghDK GoelSandeep GargTS GrewalNCERT solutions
Class 12 NCERT SolutionsClass 11 NCERT SolutionsClass 10 NCERT SolutionsClass 9 NCERT SolutionsClass 8 NCERT SolutionsClass 7 NCERT SolutionsClass 6 NCERT Solutions
