Equation of the line passing through the point −1,2,−3and perpendicular to the plane2x+3y+z+5=0
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a
x−1−1=y+21=z−3−1
b
x+1−1=y−21=z+31
c
x+12=y−23=z+31
d
x+y−3=y−12=z−31
answer is C.
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Detailed Solution
The direction ratios of any line perpendicular to the plane ax+by+cz+d=0are proportional toa,b,cThe equation of the line passing through the point x1,y1,z1and parallel to the line whose direction ratios are a,b,cisx−x1a=y−y1b=z−z1cHence, the equation of the line passing through the point −1,2,−3and perpendicular to the plane 2x+3y+z+5=0is x+12=y−23=z+31