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Q.

The equation of line passing through the points 3,p,0 and  2,q,4where  p+q=5and pq=6 is  p>q

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a

x−21=y−23=z−42

b

x−30=y−24=z−15

c

x−3−1=y−3−1=z4

d

x−3−1=y−3−1=z−14

answer is C.

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Detailed Solution

Given p+q=5 and pq=6, it implies that  p=3,q=2The given points are   3,3,0and  2,2,4The equation of the line joining the points Ax1,y1,z1,Bx2,y2,z2  isx−x1x2−x1=y−y1y2−y1=z−z1z2−z1Therefore, the equation of the line joining the points  3,3,0and  2,2,4is  x−3−1=y−3−1=z−04
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