Questions
The equation of line passing through the points and where and is
a
x−21=y−23=z−42
b
x−30=y−24=z−15
c
x−3−1=y−3−1=z4
d
x−3−1=y−3−1=z−14
detailed solution
Correct option is C
Given p+q=5 and pq=6, it implies that p=3,q=2The given points are 3,3,0and 2,2,4The equation of the line joining the points Ax1,y1,z1,Bx2,y2,z2 isx−x1x2−x1=y−y1y2−y1=z−z1z2−z1Therefore, the equation of the line joining the points 3,3,0and 2,2,4is x−3−1=y−3−1=z−04Talk to our academic expert!
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The equation of line of shortest distance between the lines is
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