Questions

The equation of the line passing through $(1, - 1, 3)$ which is perpendicular to the plane $9 x - 2 y - 5 z + 4 = 0$ is

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x1=y2=z1

x−19=y+1−2=z−3−5

x−17=y−12=z−13

x−19=y+12=z−35

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detailed solution

Correct option is B

The direction ratios of normal line to the plane 9x-2y-5z+4=0 are 9,-2,-5The equation of the line passing through (1,-1,3) which is perpendicular to the plane 9x-2y-5z+4=0 isx−19=y+1−2=z−3−5

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