The equation of a line which is perpendicular to the plane 5x+2y−8z=0 and passing through -1,0,1 is

The equation of a line passing through the point (x1,y1,z1) and perpendicular to the plane ax+by+cz+d=0 is x−x1a=y−y1b=z−z1cTherefore, the equation of a line which is perpendicular to the plane 5x+2y−8z=0 and passing through -1,0,1 is x+15=y2=z−1-8