Questions
The equation of a line which is perpendicular to the plane and passing through is
a
x+15=y2=z−1-8
b
x−15=y−10=z−1−8
c
x+18=z−12=y−02
d
x−5−1=y−20=z+21
detailed solution
Correct option is A
The equation of a line passing through the point (x1,y1,z1) and perpendicular to the plane ax+by+cz+d=0 is x−x1a=y−y1b=z−z1cTherefore, the equation of a line which is perpendicular to the plane 5x+2y−8z=0 and passing through -1,0,1 is x+15=y2=z−1-8Talk to our academic expert!
Similar Questions
The equation of the plane which passes through the z-axis and is perpendIcular to the line is
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