The equation of the line whose perpendicular distance from the origin is 3 units and the angle which the normal makes with the positive direction of x-axis is 30° is

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x+3y=3

3x+y=6

3x+y=1

x+3y=6

answer is B.

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Detailed Solution

Equation of the line is x cos a+y sin a=p where p=3,α=30∘ So the required equation is 32x+12y=3 or 3x+y=6

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