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Q.

Equation of the line x−12=y+1−1=z−34 is the line of intersection of -------

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a

x+2y+1=0=2x−z+1

b

x−y+1=0=x−2z+4

c

2x−y+3=0=x−y+z

d

x−y+z=0=x−y+3z

answer is .

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Detailed Solution

The given line is x−12=y+1−1=z−34Equate first two equations, x−12=y+1−1⇒−x+1=2y+2⇒x+2y+1=0Equate first and last equations x−12=z−34⇒2(x−1)=z−3⇒2x−z+1=0 Therefore, the given line is intersection of x+2y+1=0=2x−z+1
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