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Equation of the line $\frac{x - 1}{2} = \frac{y + 1}{- 1} = \frac{z - 3}{4}$ is the line of intersection of -------

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x+2y+1=0=2x−z+1

x−y+1=0=x−2z+4

2x−y+3=0=x−y+z

x−y+z=0=x−y+3z

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The given line is x−12=y+1−1=z−34Equate first two equations, x−12=y+1−1⇒−x+1=2y+2⇒x+2y+1=0Equate first and last equations x−12=z−34⇒2(x−1)=z−3⇒2x−z+1=0 Therefore, the given line is intersection of x+2y+1=0=2x−z+1

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Equation of the line x−12=y+1−1=z−34 is the line of intersection of -------

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Equation of the line $\frac{x - 1}{2} = \frac{y + 1}{- 1} = \frac{z - 3}{4}$ is the line of intersection of -------