The equation of the line x +y+z-1=0,4x+y-2z+2=1 written in the symmetrical form is
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a
x+11=y−2−2=z−01
b
x1=y−2=z−11
c
x+1/21=y−1−2=z−1/21
d
x−12=y+2−1=z−22
answer is A.
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Detailed Solution
x +y+z-1=0,4x+y-2z+2=1Therefore, direction ratios of the line are (-3, 6,-3), i.e., (1, -2, 1) Let z=k, then x=k- 1, y=2-2k i.e., (k - 1, 2 - 2k, k) is any point on the line Therefore, (-1 ,2,0),(0, 0, 1) and −12,1,12 are points on the lines.