The equation of the lines x + y + z - 1 =0 and 4x + y - 2z+2 =0 written in the symmetrical form is

x+y+z-1=0 4x+y-2z+2=0Therefore, the line is along the vector  (i^+j^+k^)×(4i^+j^−2k^)=3i^−6^j+3k^Let z=`k. Then x=k- 1 and y=2-2k Therefore, (k - 1, 2 - 2k, k) is any point on the line. Hence, (-1, 2,0), (0, 0, 1) and (-1/2, 1, 1/2) are the points on the line