First slide
Parabola
Question

Equation of a normal to the parabola y2 = 32x passing through its focus is 

Moderate
Solution

Equation of a normal to the parabola is 

y=mx2amam3,4a=32a=8

which passes through the focus (8, 0)

If 0=8m16m8m3=0 

m3+m=0mm2+1=0m=0

and the required equation of the normal is  y = 0.  

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