Equation of a normal to the parabola y2 = 32x passing through its focus is

Equation of a normal to the parabola is y=mx−2am−am3,4a=32⇒a=8which passes through the focus (8, 0)If 0=8m−16m−8m3=0 ⇒m3+m=0⇒mm2+1=0⇒m=0and the required equation of the normal is  y = 0.