Equation of a normal to the parabola y2 = 32x passing through its focus is
x=0
y=0
x+y−8=0
x−y−8=0
Equation of a normal to the parabola is
y=mx−2am−am3,4a=32⇒a=8
which passes through the focus (8, 0)
If 0=8m−16m−8m3=0
⇒m3+m=0⇒mm2+1=0⇒m=0
and the required equation of the normal is y = 0.